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k-1-n-tan-kpi-2n-1-2n-1-




Question Number 143463 by Dwaipayan Shikari last updated on 14/Jun/21
Π_(k=1) ^n tan(((kπ)/(2n+1)))=(√(2n+1))
$$\underset{{k}=\mathrm{1}} {\overset{{n}} {\prod}}{tan}\left(\frac{{k}\pi}{\mathrm{2}{n}+\mathrm{1}}\right)=\sqrt{\mathrm{2}{n}+\mathrm{1}} \\ $$

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