Let-a-belongs-to-an-interval-A-k-is-aconstant-such-that-k-R-and-k-lt-a-Find-out-A-in-case-a-k-a-k-a-k-a-k-

Question Number 1738 by Rasheed Sindhi last updated on 08/Sep/15

L e t a b e l o n g s t o a n i n t e r v a l A, k i s a c o n s t a n t s u c h t h a t

k \in R^{+} a n d k < a .

F i n d o u t A i n c a s e :

{(a - k)}^{a + k} ⩾ {(a + k)}^{a - k}