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Let-A-denotes-the-Set-of-Algebraic-Numbers-and-T-the-Set-of-Trancedental-Numbers-Discuss-the-following-Are-A-and-T-closed-with-respect-to-addition-and-multiplication-Are-A-0-and-T-clos




Question Number 4027 by Rasheed Soomro last updated on 27/Dec/15
Let A denotes the Set of Algebraic Numbers  and  T   the Set of Trancedental Numbers.  Discuss the following:  •Are A and T  closed with respect to    addition and multiplication ?  •Are A−{0)  and T  closed with respect to    division?
LetAdenotestheSetofAlgebraicNumbersandTtheSetofTrancedentalNumbers.Discussthefollowing:AreAandTclosedwithrespecttoadditionandmultiplication?AreA{0)andTclosedwithrespecttodivision?
Commented by Yozzii last updated on 27/Dec/15
Algebraic numbers are solutions  to finite,non−zero polynomials whose  coefficients are rational numbers  and are in one variable.  Thus, x∈A⇒ x∈Q or x∈C−{transendental complex numbers}  x∈T⇒x∉A.   Note that ∃x∈A which are irrational  e.g the solution to x^2 −2=0.  Also x∈A could be a trigonometric  function applied to a rational multiple  of π.  e.g cos3r=4cos^3 r−3cosr.  let p=cosr and cos3r=0⇒3r=2nπ±(π/2) (n∈Z)  r=(1/3)(2nπ±(π/2))  ∴ 4p^3 −3p=0 has solutions  p=cos((1/3)(2nπ±(π/2))) (n=0,1)    Under the binary operation ∗ for  addition, closure of A is provided  since A⊂C exhibits closure.  T is not closed under ∗ since, for  example, −π,π∈T⇒(π)+(−π)=0∉T.    Define ⊕ as the binary operation of  multiplication. A does exhibit closure  by virtue of C exhbiting closure  under ⊕ and A⊂C. T is not closed  under multiplication since, for 2π,(1/π)∈T,  2π⊕(1/π)=2∉T.
Algebraicnumbersaresolutionstofinite,nonzeropolynomialswhosecoefficientsarerationalnumbersandareinonevariable.Thus,xAxQorxC{transendentalcomplexnumbers}xTxA.NotethatxAwhichareirrationale.gthesolutiontox22=0.AlsoxAcouldbeatrigonometricfunctionappliedtoarationalmultipleofπ.e.gcos3r=4cos3r3cosr.letp=cosrandcos3r=03r=2nπ±π2(nZ)r=13(2nπ±π2)4p33p=0hassolutionsp=cos(13(2nπ±π2))(n=0,1)Underthebinaryoperationforaddition,closureofAisprovidedsinceACexhibitsclosure.Tisnotclosedundersince,forexample,π,πT(π)+(π)=0T.Defineasthebinaryoperationofmultiplication.AdoesexhibitclosurebyvirtueofCexhbitingclosureunderandAC.Tisnotclosedundermultiplicationsince,for2π,1πT,2π1π=2T.
Commented by Rasheed Soomro last updated on 27/Dec/15
EX_(PLANATION) ^(CELLENT)   !!!
EXPLANATIONCELLENT!!!

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