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let-b-and-r-be-two-positive-prime-numbers-such-that-b-r-and-b-r-is-a-divisor-of-138-Consider-an-arithmetic-progression-in-which-the-first-term-is-b-the-ratio-is-r-and-the-fourth-term-is-71-What-i




Question Number 74703 by Mr. K last updated on 29/Nov/19
let b and r be two positive prime   numbers such that b≠r and b×r is  a divisor of 138. Consider an   arithmetic progression in which  the first term is b, the ratio is r  and the fourth term is 71. What is the  value of b+r?
letbandrbetwopositiveprimenumberssuchthatbrandb×risadivisorof138.Consideranarithmeticprogressioninwhichthefirsttermisb,theratioisrandthefourthtermis71.Whatisthevalueofb+r?
Answered by mind is power last updated on 29/Nov/19
br∣138  138=2.69=2.3.23    b+3r=71⇒b≡−1(3)  ⇒b∈{2,23}  b+r=71−2r⇒b+r=1(2)⇒b,r are in different parite  one of them is 2  b=71−3r≤23⇒r≥((71−23)/2)=((48)/3)=16⇒r=23,b=2  b+r=25
br138138=2.69=2.3.23b+3r=71b1(3)b{2,23}b+r=712rb+r=1(2)b,rareindifferentpariteoneofthemis2b=713r23r71232=483=16r=23,b=2b+r=25

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