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Let-p-P-and-m-Z-Find-p-m-such-that-p-m-1-p-1-146410-




Question Number 4199 by Yozzii last updated on 01/Jan/16
Let p∈P and m∈Z^+ .  Find (p,m) such that p^(m−1) (p−1)=146410.
LetpPandmZ+.Find(p,m)suchthatpm1(p1)=146410.
Answered by Rasheed Soomro last updated on 01/Jan/16
p^(m−1) (p−1)=146410  146410=2×5×11^4    p∈P⇒p=2 ∣ p  is odd  For p=2,  146410 should be of 2^n  type but it  isn′t.  ∴ p is odd  ∴ p−1 is even  even factors of 146410 are 2,10,22  p−1=2,10,22 ⇒ p=3,11,23  ∵ 3 and 23 are not factors  ∴ p=11  11^(m−1) (11−1)=146410  11^(m−1) =11^4   m−1=4  m=5  (p,m)=(11,5)
pm1(p1)=146410146410=2×5×114pPp=2pisoddForp=2,146410shouldbeof2ntypebutitisnt.pisoddp1isevenevenfactorsof146410are2,10,22p1=2,10,22p=3,11,233and23arenotfactorsp=1111m1(111)=14641011m1=114m1=4m=5(p,m)=(11,5)

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