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Question Number 4716 by 123456 last updated on 28/Feb/16
lets f:[0,T]→R  does?  (1/T)∫_0 ^T f(t)dt≤(√((1/T)∫_0 ^T [f(t)]^2 dt))≤(1/T)∫_0 ^T ∣f(t)∣dt
letsf:[0,T]Rdoes?1TT0f(t)dt1TT0[f(t)]2dt1TT0f(t)dt
Commented by prakash jain last updated on 29/Feb/16
Let us say T=1  f(t)= { (2,(0<t≤0.5)),(4,(0.5<t≤1)) :}  (1/T)∫_0 ^T f(t)dt=1+2=3  (√((1/T)∫_0 ^T [f(t)]^2 dt))=(√(4×.5+16×.5))=(√(10))>3  (1/T)∫_0 ^T ∣f(t)∣dt=3<(√(10))  The first and third part on inequality evalutes  to same value if f(t)≥0.  So the given condition is not true.
LetussayT=1f(t)={20<t0.540.5<t11TT0f(t)dt=1+2=31TT0[f(t)]2dt=4×.5+16×.5=10>31TT0f(t)dt=3<10Thefirstandthirdpartoninequalityevalutestosamevalueiff(t)0.Sothegivenconditionisnottrue.

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