lim-n-1-n-n-2-4n-chiaha-daniel-

Question Number 143391 by daniel1301 last updated on 13/Jun/21

{l i m}_{n \to \infty} {(1 - \frac{n}{n - 2})}^{4 n} = ? ?

c h i a h a d a n i e l

Answered by ArielVyny last updated on 13/Jun/21

e^{4 n l n (1 - \frac{n}{n - 2})} = e^{4 n l n (0^{+})} = e^{+ \propto \times - \propto} = e^{- \propto} = 0

Commented by daniel1301 last updated on 13/Jun/21

t h a n k y o u