lim-x-0-cos-x-1-x-2-2-x-4-24-x-6- Tinku Tara June 3, 2023 Limits 0 Comments FacebookTweetPin Question Number 133583 by bemath last updated on 23/Feb/21 limx→0cosx−1+x22−x424x6 Answered by EDWIN88 last updated on 23/Feb/21 limx→01−x22+x424−x6720+R(x6)−1+x22−x424x6=limx→0−x6720+R(x6)x6=−1720 Terms of Service Privacy Policy Contact: info@tinkutara.com FacebookTweetPin Post navigation Previous Previous post: Question-133579Next Next post: Question-68046 Leave a Reply Cancel replyYour email address will not be published. Required fields are marked *Comment * Name * Save my name, email, and website in this browser for the next time I comment.