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lim-x-0-xln-sinx-




Question Number 132226 by kaivan.ahmadi last updated on 12/Feb/21
lim_(x→0^+ )   xln(sinx)
limx0+xln(sinx)
Answered by Olaf last updated on 12/Feb/21
sinx ∼_0  x  ⇒ lim_(x→0)  xln(sinx) = lim_(x→0)  xlnx = 0
sinx0xlimx0xln(sinx)=limx0xlnx=0

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