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lim-x-pi-2-sin-x-cos-x-tan-x-




Question Number 70653 by naka3546 last updated on 06/Oct/19
lim_(x→(π/2))   (sin x − cos x)^(tan x)   =  ...
limxπ2(sinxcosx)tanx=
Commented by kaivan.ahmadi last updated on 06/Oct/19
lim_(x→(π/2)) (sinx−cosx−1)tanx=  lim_(x→(π/2)) (sin^2 x−sinx−tanx)=−∞  ⇒lim_(x→(π/2)) (sinx−cosx)^(tanx) =e^(−∞) =0
limxπ2(sinxcosx1)tanx=limxπ2(sin2xsinxtanx)=limxπ2(sinxcosx)tanx=e=0
Answered by sadimuhmud 136 last updated on 06/Oct/19

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