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ln-e-y-dy-




Question Number 76958 by malikmasood3535@gmail.com last updated on 01/Jan/20
∫ln e^y dy
$$\int{ln}\:{e}^{{y}} {dy} \\ $$
Commented by kaivan.ahmadi last updated on 01/Jan/20
∫ydy=(y^2 /2)+C
$$\int{ydy}=\frac{{y}^{\mathrm{2}} }{\mathrm{2}}+{C} \\ $$
Answered by peter frank last updated on 01/Jan/20
∫yln e.dy  ∫ydy  (y^2 /2)+A
$$\int{y}\mathrm{ln}\:{e}.{dy} \\ $$$$\int{ydy} \\ $$$$\frac{{y}^{\mathrm{2}} }{\mathrm{2}}+{A} \\ $$$$ \\ $$

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