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ln-e-y-dy-




Question Number 76958 by malikmasood3535@gmail.com last updated on 01/Jan/20
∫ln e^y dy
lneydy
Commented by kaivan.ahmadi last updated on 01/Jan/20
∫ydy=(y^2 /2)+C
ydy=y22+C
Answered by peter frank last updated on 01/Jan/20
∫yln e.dy  ∫ydy  (y^2 /2)+A
ylne.dyydyy22+A

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