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ln-x-x-1-dx-




Question Number 134716 by metamorfose last updated on 06/Mar/21
∫((ln(x))/(x−1))dx=...??
ln(x)x1dx=??
Answered by Lordose last updated on 06/Mar/21
∫((ln(x))/(x−1))dx =^(u=x−1) ∫((ln(1+u))/u)du = −Li_2 (−u) + C  Ω = −Li_2 (1−x) + C
ln(x)x1dx=u=x1ln(1+u)udu=Li2(u)+CΩ=Li2(1x)+C

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