log-2-x-log-3-x-1-x-

Question Number 131884 by Study last updated on 09/Feb/21

{l o g}_{2} x + {l o g}_{3} x = 1 x = ?

Answered by EDWIN88 last updated on 09/Feb/21

\frac{\ln x}{\ln 2} + \frac{\ln x}{\ln 3} = 1

\ln x (\frac{1}{\ln 2} + \frac{1}{\ln 3}) = 1

\ln x = \frac{\ln 2 . \ln 3}{\ln 6} \Rightarrow x = e^{(\frac{\ln 2 . \ln 3}{\ln 6})} \approx 1.529592

e^{\frac{\ln 2 \times \ln 3}{\ln 6}}

1.529592

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