log-2-x-logx-2-3-0-x-

Question Number 6111 by Kasih last updated on 14/Jun/16

{l o g}^{2} x + {l o g x}^{2} - 3 = 0, x = ?

Answered by prakash jain last updated on 14/Jun/16

\log x = u

u^{2} + 2 u - 3 = 0 \Rightarrow (u + 3) (u - 1) = 0

\Rightarrow u = - 3 o r u = 1

\log x = - 3 o r \log x = 1

x = 10^{- 3} o r x = 10^{1}