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log-5-27-log-9-125-log-16-12-a-61-36-b-9-4-c-61-20-d-41-12-e-7-2-




Question Number 65970 by gunawan last updated on 07/Aug/19
log_5 (√(27))×log_9 125+log_(16) 12=...  a. ((61)/(36))  b. (9/4)  c. ((61)/(20))  d. ((41)/(12))  e. (7/2)
log527×log9125+log1612=a.6136b.94c.6120d.4112e.72
Answered by MJS last updated on 07/Aug/19
log_b  a =((ln a)/(ln b))  ((ln (√(27)))/(ln 5))×((ln 125)/(ln 9))+((ln 12)/(ln 16))=((ln 3^(3/2) )/(ln 5))×((ln 5^3 )/(ln 3^2 ))+((ln 2^2 3)/(ln 2^4 ))=  =(((3/2)ln 3)/(ln 5))×((3ln 5)/(2ln 3))+((2ln 2 +ln 3)/(4ln 2))=(9/4)+(1/2)+((ln 3)/(4ln 2))=  =((11)/4)+((ln 3)/(4ln 2))  please check given equation
logba=lnalnbln27ln5×ln125ln9+ln12ln16=ln332ln5×ln53ln32+ln223ln24==32ln3ln5×3ln52ln3+2ln2+ln34ln2=94+12+ln34ln2==114+ln34ln2pleasecheckgivenequation

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