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log-abc-b-3-log-abc-c-4-log-abc-a-




Question Number 12093 by uni last updated on 13/Apr/17
log_(abc) b=3  log_(abc) c=4  log_(abc) a=?
logabcb=3logabcc=4logabca=?
Answered by ajfour last updated on 13/Apr/17
log _(abc) abc =(log _(abc) a)+(log _(abc) b)+(log _(abc) c)=1  (log _(abc) a)+3+4 =1  log _(abc) a =−6 .
logabcabc=(logabca)+(logabcb)+(logabcc)=1(logabca)+3+4=1logabca=6.

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