Question Number 77505 by jagoll last updated on 07/Jan/20
$${many}\:{three}\: \\ $$$${digit}\:{multiples}\:{of}\:{three}\:{that} \\ $$$${can}\:{be}\:{made}\:{from}\:{the}\:{number} \\ $$$$\mathrm{0},\mathrm{1},\mathrm{2},\mathrm{3},\mathrm{4},\mathrm{5},\mathrm{6},\mathrm{7}\:{without}\:{repetition}? \\ $$
Commented by jagoll last updated on 07/Jan/20
$${sir}\:{W}\:{i}\:{got}\:{the}\:{result}\:\mathrm{104}.\:{it}\:{correct}? \\ $$
Answered by MJS last updated on 08/Jan/20
$$\mathrm{4}\:\mathrm{possibilities}\:\mathrm{each} \\ $$$$\mathrm{012}\:\:\mathrm{015}\:\:\mathrm{024}\:\:\mathrm{027}\:\:\mathrm{036}\:\:\mathrm{045}\:\:\mathrm{057} \\ $$$$\mathrm{6}\:\mathrm{possibilities}\:\mathrm{each} \\ $$$$\mathrm{123}\:\:\mathrm{126}\:\:\mathrm{135}\:\:\mathrm{147}\:\:\mathrm{156}\:\:\mathrm{234}\:\:\mathrm{237} \\ $$$$\mathrm{246}\:\:\mathrm{267}\:\:\mathrm{345}\:\:\mathrm{357}\:\:\mathrm{456}\:\:\mathrm{567} \\ $$$$\mathrm{7}×\mathrm{4}+\mathrm{13}×\mathrm{6}=\mathrm{106} \\ $$
Commented by jagoll last updated on 08/Jan/20
$${thanks}\:{you}\:{sir} \\ $$