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More-generalized-form-of-Q-1296-f-ax-b-f-x-n-f-x-




Question Number 1320 by Rasheed Soomro last updated on 22/Jul/15
More generalized form  of Q 1296  f(ax+b)=[f(x)]^n   f(x)=?
$${More}\:{generalized}\:{form}\:\:{of}\:{Q}\:\mathrm{1296} \\ $$$${f}\left({ax}+{b}\right)=\left[{f}\left({x}\right)\right]^{{n}} \\ $$$${f}\left({x}\right)=? \\ $$

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