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Question Number 143698 by Dwaipayan Shikari last updated on 17/Jun/21
My first Contribution to this forum. One year later Q 98831
$$\:{My}\:{first}\:{Contribution}\:{to}\:{this}\:{forum}.\: \\ $$$${One}\:{year}\:{later}\: \\ $$$${Q}\:\mathrm{98831} \\ $$
Commented by Dwaipayan Shikari last updated on 17/Jun/21
Mad Question on that same day. Mr.MJS said that it Consists Hypergeometric function .I didn′t know About Hypergeometric functions Q98951
$${Mad}\:{Question}\:{on}\:{that}\:{same}\:{day}.\:{Mr}.{MJS}\:{said}\:{that}\:{it} \\ $$$${Consists}\:{Hypergeometric}\:{function}\:.{I}\:{didn}'{t}\:{know} \\ $$$${About}\:{Hypergeometric}\:{functions} \\ $$$${Q}\mathrm{98951} \\ $$
Commented by Dwaipayan Shikari last updated on 17/Jun/21
Another Mad Question! Q 98929
$${Another}\:{Mad}\:{Question}! \\ $$$${Q}\:\mathrm{98929} \\ $$
Commented by Dwaipayan Shikari last updated on 17/Jun/21
∫tan^(1/5) (x) cot(x)sec(x)dx =∫((sin^(−4/5) x)/(cos^(1/5) x)) dx sinx=t =∫t^(−4/5) (1−t^2 )^(−3/5) dt =Σ_(n=0) ^∞ ((((3/5))_n )/(n!))∫t^(−4/5) t^(2n) dt=Σ_(n=0) ^∞ ((((3/5))_n )/(n!)).(1/(2n+(1/5)))t^(2n+(4/5)) +C =(t^(1/5) /2)Σ_(n=0) ^∞ ((((3/5))_n )/(n!(n+(1/(10)))))t^(2n) +C =(t^(1/5) /2)Σ_(n=0) ^∞ ((((3/5))_n Γ(n+(1/(10))))/(n!Γ(n+((11)/(10)))))t^(2n) =5(t)^(1/5) Σ_(n=0) ^∞ ((((3/5))_n ((1/(10)))_n )/(n!(((11)/(10)))_n ))t^(2n) +C =5(t)^(1/5) _2 F_1 ((3/5),(1/(10))∣((11)/(10)),t^2 )+C =5((sin(x)))^(1/5) _2 F_1 ((3/5),(1/(10))∣((11)/(10));sin^2 x)+C
$$\int{tan}^{\frac{\mathrm{1}}{\mathrm{5}}} \left({x}\right)\:{cot}\left({x}\right){sec}\left({x}\right){dx} \\ $$$$=\int\frac{{sin}^{−\mathrm{4}/\mathrm{5}} {x}}{{cos}^{\mathrm{1}/\mathrm{5}} {x}}\:{dx}\:\:\:\:\:\:\:\:\:\:\:{sinx}={t} \\ $$$$=\int{t}^{−\mathrm{4}/\mathrm{5}} \left(\mathrm{1}−{t}^{\mathrm{2}} \right)^{−\mathrm{3}/\mathrm{5}} {dt}\:\:\: \\ $$$$=\underset{{n}=\mathrm{0}} {\overset{\infty} {\sum}}\frac{\left(\frac{\mathrm{3}}{\mathrm{5}}\right)_{{n}} }{{n}!}\int{t}^{−\mathrm{4}/\mathrm{5}} {t}^{\mathrm{2}{n}} {dt}=\underset{{n}=\mathrm{0}} {\overset{\infty} {\sum}}\frac{\left(\frac{\mathrm{3}}{\mathrm{5}}\right)_{{n}} }{{n}!}.\frac{\mathrm{1}}{\mathrm{2}{n}+\frac{\mathrm{1}}{\mathrm{5}}}{t}^{\mathrm{2}{n}+\frac{\mathrm{4}}{\mathrm{5}}} +{C} \\ $$$$=\frac{{t}^{\mathrm{1}/\mathrm{5}} }{\mathrm{2}}\underset{{n}=\mathrm{0}} {\overset{\infty} {\sum}}\frac{\left(\frac{\mathrm{3}}{\mathrm{5}}\right)_{{n}} }{{n}!\left({n}+\frac{\mathrm{1}}{\mathrm{10}}\right)}{t}^{\mathrm{2}{n}} +{C} \\ $$$$=\frac{{t}^{\mathrm{1}/\mathrm{5}} }{\mathrm{2}}\underset{{n}=\mathrm{0}} {\overset{\infty} {\sum}}\frac{\left(\frac{\mathrm{3}}{\mathrm{5}}\right)_{{n}} \Gamma\left({n}+\frac{\mathrm{1}}{\mathrm{10}}\right)}{{n}!\Gamma\left({n}+\frac{\mathrm{11}}{\mathrm{10}}\right)}{t}^{\mathrm{2}{n}} =\mathrm{5}\sqrt[{\mathrm{5}}]{{t}}\underset{{n}=\mathrm{0}} {\overset{\infty} {\sum}}\frac{\left(\frac{\mathrm{3}}{\mathrm{5}}\right)_{{n}} \left(\frac{\mathrm{1}}{\mathrm{10}}\right)_{{n}} }{{n}!\left(\frac{\mathrm{11}}{\mathrm{10}}\right)_{{n}} }{t}^{\mathrm{2}{n}} +{C} \\ $$$$=\mathrm{5}\sqrt[{\mathrm{5}}]{{t}}\:_{\mathrm{2}} {F}_{\mathrm{1}} \left(\frac{\mathrm{3}}{\mathrm{5}},\frac{\mathrm{1}}{\mathrm{10}}\mid\frac{\mathrm{11}}{\mathrm{10}},{t}^{\mathrm{2}} \right)+{C} \\ $$$$=\mathrm{5}\sqrt[{\mathrm{5}}]{{sin}\left({x}\right)}\:_{\mathrm{2}} {F}_{\mathrm{1}} \left(\frac{\mathrm{3}}{\mathrm{5}},\frac{\mathrm{1}}{\mathrm{10}}\mid\frac{\mathrm{11}}{\mathrm{10}};{sin}^{\mathrm{2}} {x}\right)+{C} \\ $$
Commented by Ar Brandon last updated on 17/Jun/21
Happy Birthday on this forum. Haha ! In one year I think you′ve progressed a lot. Thanks for your teachings, Sir. 😉
$$\mathrm{Happy}\:\mathrm{Birthday}\:\mathrm{on}\:\mathrm{this}\:\mathrm{forum}.\:\mathrm{Haha}\:!\:\mathrm{In}\:\mathrm{one}\: \\ $$$$\mathrm{year}\:\mathrm{I}\:\mathrm{think}\:\mathrm{you}'\mathrm{ve}\:\mathrm{progressed}\:\mathrm{a}\:\mathrm{lot}.\:\mathrm{Thanks} \\ $$$$\:\mathrm{for}\:\mathrm{your}\:\mathrm{teachings},\:\mathrm{Sir}. \\ $$😉
Commented by Dwaipayan Shikari last updated on 17/Jun/21
Hahahaha Young Boys .But i have turned myself into a Cat. I was a Black hole. It will take another year to become a Man
$$\:{Hahahaha}\:\mathrm{Y}{oung}\:{Boys}\:.{But}\:{i}\:{have}\: \\ $$$${turned}\:{myself}\:{into}\:{a}\:{Cat}. \\ $$$${I}\:{was}\:{a}\:{Black}\:{hole}.\:{It}\:{will} \\ $$$${take}\:{another}\:{year}\:{to}\:{become}\:{a}\: \\ $$$${Man} \\ $$

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