Question Number 141757 by Ndala last updated on 23/May/21
$$\Gamma\left(\mathrm{n}+\frac{\mathrm{1}}{\mathrm{2}}\right)=\frac{\sqrt{\pi}\centerdot\Gamma\left(\mathrm{2n}+\mathrm{1}\right)}{\mathrm{2}^{\mathrm{2n}} \Gamma\left(\mathrm{n}+\mathrm{1}\right)} \\ $$
Commented by Ndala last updated on 23/May/21
$$\mathrm{someone}\:\mathrm{to}\:\mathrm{help}\:\mathrm{me}\:\mathrm{with}\:\mathrm{the}\:\mathrm{proof}.\:\mathrm{Please} \\ $$