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n-2-n-n-natural-number-

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Question Number 66549 by aditya@345 last updated on 17/Aug/19
((n^2 !)/((n!)^n ))=natural number.
$$\frac{\mathrm{n}^{\mathrm{2}} !}{\left(\mathrm{n}!\right)^{\mathrm{n}} }=\mathrm{natural}\:\mathrm{number}. \\ $$

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