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n-4-1-8n-Euler-totient-function-Solve-for-n-N-




Question Number 143085 by Dwaipayan Shikari last updated on 09/Jun/21
φ(n^4 +1)=8n      φ:Euler totient function  Solve for n∈N
$$\phi\left({n}^{\mathrm{4}} +\mathrm{1}\right)=\mathrm{8}{n}\:\:\:\:\:\:\phi:{Euler}\:{totient}\:{function} \\ $$$${Solve}\:{for}\:{n}\in\mathbb{N} \\ $$

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