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n-c-n-n1-n-n-




Question Number 11343 by jaskaurrangerleader@gmail.com last updated on 21/Mar/17
n_c_n  =((n1)/((n−n)))
$${n}_{\boldsymbol{\mathrm{c}}_{\boldsymbol{\mathrm{n}}} } =\frac{{n}\mathrm{1}}{\left({n}−{n}\right)} \\ $$
Commented by FilupS last updated on 21/Mar/17
(n/(n−n))=undefined
$$\frac{{n}}{{n}−{n}}=\mathrm{undefined} \\ $$

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