Menu Close

n-i-n-i-i-sin-n-i-




Question Number 4785 by Dnilka228 last updated on 10/Mar/16
n^i (n/(i×i))≈sin n^i +α
nini×isinni+α
Commented by Dnilka228 last updated on 10/Mar/16
n^i (n/(i×i))≠sin α+n^i   (√n^i )=sin n+sin i×(√2)  sin n^i ×f(x)=a+b=1,5  a=1, b=0,5
nini×isinα+nini=sinn+sini×2sinni×f(x)=a+b=1,5a=1,b=0,5
Commented by Dnilka228 last updated on 10/Mar/16
If a=1, sin a=sin 1  If b=0,5, sin b=sin 0,5
Ifa=1,sina=sin1Ifb=0,5,sinb=sin0,5

Leave a Reply

Your email address will not be published. Required fields are marked *