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n-m-Z-n-n-n-1-n-2-if-n-m-where-we-know-the-value-m-but-not-n-can-we-solve-for-n-




Question Number 4234 by Filup last updated on 04/Jan/16
n, m∈Z  n!=n(n−1)(n−2)...    if n!=m where we know the value  m but not n, can we solve for n?
n,mZn!=n(n1)(n2)ifn!=mwhereweknowthevaluembutnotn,canwesolveforn?
Commented by prakash jain last updated on 04/Jan/16
One option:  n=m/2/3/4/5/6..  until no more divisions  are possible.  m=720  720/2=360,360/3=120,120/4=30,30/5=6
Oneoption:n=m/2/3/4/5/6..untilnomoredivisionsarepossible.m=720720/2=360,360/3=120,120/4=30,30/5=6

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