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n-N-a-5-a-13-0-b-n-1-b-n-2-b-n-a-n-1-a-n-a-1-




Question Number 141693 by Fikret last updated on 22/May/21
n∈N^+   a_5 =a_(13) =0  b_(n+1) −b_n =2  b_n =a_(n+1) −a_n    ⇒  a_1 =?
nN+a5=a13=0bn+1bn=2bn=an+1ana1=?

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