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n-N-a-5-a-13-0-b-n-1-b-n-2-b-n-a-n-1-a-n-a-1-




Question Number 141693 by Fikret last updated on 22/May/21
n∈N^+   a_5 =a_(13) =0  b_(n+1) −b_n =2  b_n =a_(n+1) −a_n    ⇒  a_1 =?
$${n}\in{N}^{+} \\ $$$${a}_{\mathrm{5}} ={a}_{\mathrm{13}} =\mathrm{0} \\ $$$${b}_{{n}+\mathrm{1}} −{b}_{{n}} =\mathrm{2} \\ $$$${b}_{{n}} ={a}_{{n}+\mathrm{1}} −{a}_{{n}} \:\:\:\Rightarrow\:\:{a}_{\mathrm{1}} =? \\ $$$$ \\ $$

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