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Question Number 139949 by mnjuly1970 last updated on 02/May/21
                .........nice .... ∗ ....∗ .... ∗ ....calculus(I)           𝛗=  lim_(x→0^+ ) (((cos((√x) ))^(1/3)  )^(cot(x)) =??          solution.........         sin(x) ≈ x        (x → 0 )         𝛗:=  lim_(x→0^+ ) {(cos((√x) ))^(1/3) }^(cot(x)) =lim_(x→0^+ ) {(1−(x/2))^(cot(x)) }^(1/3)              :=lim_(x→0^+ )  {(1−(x/2))^(1/(sin(x)≈x)) }^((cos(x))/3) =_(cos(x)→1  (x →0)) ^(⟨ lim_(x→0) (1−ax)^(1/x) =(1/e^( a) )  ⟩)  e^((−1)/6) = (((1/e) ))^(1/6)    ....
nice....calculus(I)ϕ=limx0+(cos(x3)cot(x)=??solutionsin(x)x(x0)ϕ:=limx0+{(cos(x))13}cot(x)=limx0+{(1x2)cot(x)}13:=limx0+{(1x2)1sin(x)x}cos(x)3=limx0(1ax)1x=1eacos(x)1(x0)e16=1e6.

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