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Question Number 139521 by mnjuly1970 last updated on 28/Apr/21
              #   nice ... calculus#          if    (pq)^(sin^2 (x)) +(pq)^(cos^2 (x)) =p+q            then    tan(x)=?
You can't use 'macro parameter character #' in math modeif(pq)sin2(x)+(pq)cos2(x)=p+qthentan(x)=?
Answered by qaz last updated on 28/Apr/21
≪1≫:p=q=0   tan x=???  ≪2≫:p=q=1   tan x=???  ≪3≫:p,q∈(0,1)∪(1,∞),pq≠1  (pq)^(sin^2 x) +(pq)^(cos^2 x)   =(pq)^(sin^2 x) +(pq)^(1−sin^2 x) =p+q  ⇒   sin^2 x=log_((pq)) p     cos^2 x=log_((pq)) q  or   sin^2 x=log_((pq)) q      cos^2 x=log_((pq)) p  tan x=(√(log_p q))     or  (√(log_q p))  ≪4≫:p,q∈C   tan x=???  .....
1≫:p=q=0tanx=???2≫:p=q=1tanx=???3≫:p,q(0,1)(1,),pq1(pq)sin2x+(pq)cos2x=(pq)sin2x+(pq)1sin2x=p+qsin2x=log(pq)pcos2x=log(pq)qorsin2x=log(pq)qcos2x=log(pq)ptanx=logpqorlogqp4≫:p,qCtanx=???..

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