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Question Number 7610 by Tawakalitu. last updated on 06/Sep/16
obtain the value of   (a^(1/2) +b^(1/2) +c^(1/2) )(a^(1/2) −b^(1/2) +c^(1/2) )(a^(1/2) −b^(1/2) +c^(1/2) )(b^(1/2) +c^(1/2) −a^(1/2) )
obtainthevalueof(a1/2+b1/2+c1/2)(a1/2b1/2+c1/2)(a1/2b1/2+c1/2)(b1/2+c1/2a1/2)
Commented by Rasheed Soomro last updated on 06/Sep/16
Perhaps you mean  (a^(1/2) +b^(1/2) +c^(1/2) )(a^(1/2) −b^(1/2) +c^(1/2) )(a^(1/2) +b^(1/2) −c^(1/2) )(b^(1/2) +c^(1/2) −a^(1/2) )
Perhapsyoumean(a1/2+b1/2+c1/2)(a1/2b1/2+c1/2)(a1/2+b1/2c1/2)(b1/2+c1/2a1/2)
Commented by Tawakalitu. last updated on 06/Sep/16
Alright sir.. thank you. is like that.
Alrightsir..thankyou.islikethat.
Answered by Rasheed Soomro last updated on 06/Sep/16
(a^(1/2) +b^(1/2) +c^(1/2) )(a^(1/2) −b^(1/2) +c^(1/2) )(a^(1/2) +b^(1/2) −c^(1/2) )(b^(1/2) +c^(1/2) −a^(1/2) )   Let  a^(1/2) =p , b^(1/2) =q , c^(1/2) =r  (p+q+r)(p−q+r)(p+q−r)(−p+q+r)  {(p+r)+q}{(p+r)−q}{q+(p−r)}{q−(p−r)}  {(p+r)^2 −q^2 }{q^2 −(p−r)^2 }  (p^2 +2pr+r^2 −q^2 )(q^2 −p^2 +2pr−r^2 )  {2pr+(p^2 −q^2 +r^2 )}{2pr−(p^2 −q^2 +r^2 )}  (2pr)^2 −(p^2 −q^2 +r^2 )^2   4p^2 r^2 −(p^4 +q^4 +r^4 −2p^2 q^2 −2q^2 r^2 +2p^2 r^2 )  2p^2 r^2 −p^4 −q^4 −r^4 +2p^2 q^2 +2q^2 r^2   p=a^(1/2) ⇒p^2 =a⇒p^4 =a^2   q=b^(1/2) ⇒q^2 =b⇒q^4 =b^2   r=c^(1/2) ⇒r^2 =c⇒r^4 =c^2   2p^2 r^2 −p^4 −q^4 −r^4 +2p^2 q^2 +2q^2 r^2                  =2ac−a^2 −b^2 −c^2 +2ab+2bc                  =−(a^2 +b^2 +c^2 −2ab−2bc−2ca)
(a1/2+b1/2+c1/2)(a1/2b1/2+c1/2)(a1/2+b1/2c1/2)(b1/2+c1/2a1/2)Leta1/2=p,b1/2=q,c1/2=r(p+q+r)(pq+r)(p+qr)(p+q+r){(p+r)+q}{(p+r)q}{q+(pr)}{q(pr)}{(p+r)2q2}{q2(pr)2}(p2+2pr+r2q2)(q2p2+2prr2){2pr+(p2q2+r2)}{2pr(p2q2+r2)}(2pr)2(p2q2+r2)24p2r2(p4+q4+r42p2q22q2r2+2p2r2)2p2r2p4q4r4+2p2q2+2q2r2p=a1/2p2=ap4=a2q=b1/2q2=bq4=b2r=c1/2r2=cr4=c22p2r2p4q4r4+2p2q2+2q2r2=2aca2b2c2+2ab+2bc=(a2+b2+c22ab2bc2ca)
Commented by Tawakalitu. last updated on 06/Sep/16
wow, thank you sir. God bless you
wow,thankyousir.Godblessyou

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