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P-x-1-P-x-1-4x-2-8x-a-5-a-




Question Number 11024 by ABD last updated on 07/Mar/17
P(x+1)×P(x−1)=4x^2 +8x+a−5  a=?
P(x+1)×P(x1)=4x2+8x+a5a=?
Answered by ajfour last updated on 07/Mar/17
let P(x) = bx+c  Then P(x+1)×P(x−1)  =(bx+b+c)(bx−b+c)  =(bx+c)^2 −b^2    = 4(x+1)^2 +a−9  so, b=c=±2. and a−9=−b^2   thus  a−9 = −4              a=5  .
letP(x)=bx+cThenP(x+1)×P(x1)=(bx+b+c)(bxb+c)=(bx+c)2b2=4(x+1)2+a9so,b=c=±2.anda9=b2thusa9=4a=5.

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