p-x-x-1-2-Q-x-3x-8-p-x-x-2-Q-x-R-R- Tinku Tara June 3, 2023 None 0 Comments FacebookTweetPin Question Number 144060 by Khalmohmmad last updated on 21/Jun/21 p(x)=(x−1)2Q(x)+3x+8p(x)=(x−2)Q(x)+RR=? Commented by Rasheed.Sindhi last updated on 21/Jun/21 Q(x)issameinbothcases!!!? Answered by Rasheed.Sindhi last updated on 21/Jun/21 p(x)=(x−1)2Q1(x)+3x+8…..(i)p(x)=(x−2)Q2(x)+R…..(ii);R=?∙LetQ1(x)=q(constantp(x)=(x−1)2q+3x+8=qx2−2xq+q+3x+8=qx2+(3−2q)x+q+8Whendividedbyx−2R=q(2)2+(3−2q)(2)+q+8R=4q+6−4q+q+8=q+14∙Q1(x)=ax+bp(x)=(x−1)2Q1(x)+3x+8p(x)=(x−1)2(ax+b)+3x+8=(x2−2x+1)(ax+b)+3x+8=ax3+bx2−2ax2−2bx+ax+b+3x+8=ax3+(b−2a)x2+(a+3−2b)x+b+8Whendividedbyx−2R=p(2)=a(2)3+(b−2a)(2)2+(a+3−2b)(2)+b+8=8a+4b−8a+2a+6−4b+b+8=2a+b+14Nouniqueanswer.RdependsuponQ1(x). Answered by Rasheed.Sindhi last updated on 21/Jun/21 p(x)=(x−1)2Q1(x)+3x+8p(x)=(x−2)Q2(x)+R;R=?p(x)whenisdividedbyx−2givingremainderR(x−1)2Q1(x)+3x+8isdividedbyx−2givingremainderRR=p(2)=(2−1)2Q1(2)+3(2)+8R=p(2)=Q1(2)+14∙LetQ1(x)=q(constant)R=q+14∙LetQ1(x)=ax+bR=Q1(2)+14=a(2)+b+14R=2a+b+14∙LetQ1(x)=ax2+bx+cR=a(2)2+b(2)+c+14R=4a+2b+c+14RdependsonQ1(x)(orQ2(x)).It′snotunique. Terms of Service Privacy Policy Contact: info@tinkutara.com FacebookTweetPin Post navigation Previous Previous post: Question-144062Next Next post: Question-144061 Leave a Reply Cancel replyYour email address will not be published. Required fields are marked *Comment * Name * Save my name, email, and website in this browser for the next time I comment.