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pH-1-2-14-pK-b-pK-a-




Question Number 9347 by An2812 last updated on 02/Dec/16
pH = (1/2) (14 − pK_b  + pK_a  )
$$\mathrm{pH}\:=\:\frac{\mathrm{1}}{\mathrm{2}}\:\left(\mathrm{14}\:−\:\mathrm{pK}_{\mathrm{b}} \:+\:\mathrm{pK}_{\mathrm{a}} \:\right) \\ $$

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