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pH-pK-a-lg-C-b-C-a-




Question Number 9348 by An2812 last updated on 02/Dec/16
pH = pK_a  + lg(C_b /C_a )
$$\mathrm{pH}\:=\:\mathrm{pK}_{\mathrm{a}} \:+\:\mathrm{lg}\frac{\mathrm{C}_{\mathrm{b}} }{\mathrm{C}_{\mathrm{a}} } \\ $$

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