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pi-180-pi-3-141-pi-Solve-find-n-N-k-1-sin-2-k-10-n-pi-k-k-1-sin-2-k-10-n-e-k-0-




Question Number 9407 by geovane10math last updated on 06/Dec/16
π = 180° = Π  π = 3,141... = π  Solve (find n ∈ N):  Σ_(k=1) ^∞ ((sin(2Πk∙10^n π))/k) + Σ_(k=1) ^∞ ((sin(2Πk∙10^n e))/k) = 0
π=180°=Ππ=3,141=πSolve(findnN):k=1sin(2Πk10nπ)k+k=1sin(2Πk10ne)k=0

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