pi-2-pi-2-sin-x-cos-x-dx-pi-2-pi-2-sin-x-cos-x-cos-2nx-dx-pi-2-pi-2-sin-x-cos-x-sin-2nx-dx-n-N- Tinku Tara June 3, 2023 Geometry 0 Comments FacebookTweetPin Question Number 630 by 123456 last updated on 15/Feb/15 ∫+π2−π2sinxcosxdx∫+π2−π2sinxcosxcos(2nx)dx∫+π2−π2sinxcosxsin(2nx)dxn∈N∗ Commented by prakash jain last updated on 15/Feb/15 ∫−π2π2sinxcosxdx=∫−π20sinxcosxdx+∫0π2sinxcosxdxbothintegraldontconverge. Terms of Service Privacy Policy Contact: info@tinkutara.com FacebookTweetPin Post navigation Previous Previous post: 3-2-2-x-1-3-x-1-2-dx-Next Next post: e-3x-cosxdx-help-me-please- Leave a Reply Cancel replyYour email address will not be published. Required fields are marked *Comment * Name * Save my name, email, and website in this browser for the next time I comment.