please-help-me-find-the-term-independent-of-x-in-the-expansion-of-x-3-x-12-

Question Number 70310 by Rio Michael last updated on 03/Oct/19

p l e a s e h e l p m e f i n d t h e t e r m i n d e p e n d e n t o f x

i n t h e e x p a n s i o n o f

{(x + \frac{3}{x})}^{- 12}

Commented by mr W last updated on 03/Oct/19

a l l t e r m s a r e x d e p e n d e n t!

Answered by MJS last updated on 03/Oct/19

{(\frac{x^{2} + 3}{x})}^{- 12} = {(\frac{x}{x^{2} + 3})}^{12} \Rightarrow no term independent of x

Answered by mind is power last updated on 03/Oct/19

{(x + \frac{3}{x})}^{12} ?

Commented by Kunal12588 last updated on 03/Oct/19

t h e n a n s w e r w o u l d b e 7 t h t e r m .

Commented by Rio Michael last updated on 03/Oct/19

t h a n k s g u y s

Commented by Rio Michael last updated on 03/Oct/19

n o, t o t h e - 12, i t c a m e o n a n o f f i c i a l e x a m i n a t i o n p a p e r

a n d i t r i e d a n d c o u l d n t s o l v e

Answered by MJS last updated on 03/Oct/19

{(x + \frac{3}{x})}^{- 12} = {(\frac{x}{x^{2} + 3})}^{12} =

= \frac{1}{{(x^{2} + 3)}^{6}} - \frac{18}{{(x^{2} + 3)}^{7}} + \frac{135}{{(x^{2} + 3)}^{8}} - \frac{540}{{(x^{2} + 3)}^{9}} + \frac{1215}{{(x^{2} + 3)}^{10}} - \frac{1458}{{(x^{2} + 3)}^{11}} + \frac{729}{{(x^{2} + 3)}^{12}}

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