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Question Number 75504 by mathocean1 last updated on 12/Dec/19

please sirs i would like that you help me to

show this :

\sin (\frac{π}{3} + x) \sin (\frac{π}{3} - x) = \frac{3}{4} - \sin^{2} x

Answered by som(math1967) last updated on 12/Dec/19

s i n (\frac{π}{3} + x) s i n (\frac{π}{3} - x)

= {s i n}^{2} \frac{π}{3} - {s i n}^{2} x ★

= \frac{3}{4} - {s i n}^{2} x

★ s i n (A + B) s i n (A - B) = {s i n}^{2} A - {s i n}^{2} B

Commented by mathocean1 last updated on 12/Dec/19

thank you sir