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Powers-of-Monomials-Alg-0-6p-5-3-




Question Number 2968 by Karting7442 last updated on 01/Dec/15
Powers of Monomials       Alg.    (0.6p^5 )^3
PowersofMonomialsAlg.(0.6p5)3
Answered by Filup last updated on 02/Dec/15
=0.6^3 p^(15)     0.6=(6/(10))⇒0.6^2 =((36)/(100))=0.36    =0.36p^(15)
=0.63p150.6=6100.62=36100=0.36=0.36p15
Commented by Yozzi last updated on 02/Dec/15
0.6^3 =0.36×0.6=0.216
0.63=0.36×0.6=0.216
Commented by Filup last updated on 03/Dec/15
oops I missread
oopsImissread

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