Question Number 2967 by Karting7442 last updated on 01/Dec/15
$${Powers}\:{of}\:{Monomials}\:\:\:\:\:\:{Alg}. \\ $$$$ \\ $$$$\left(\frac{\mathrm{3}}{\mathrm{5}}{a}^{\mathrm{6}} {b}^{\mathrm{9}} \right)^{\mathrm{2}} \\ $$
Answered by Filup last updated on 02/Dec/15
$$=\frac{\mathrm{9}}{\mathrm{25}}{a}^{\mathrm{12}} {b}^{\mathrm{18}} \\ $$