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prove-a-3-b-3-c-3-3abc-a-b-c-0-




Question Number 8991 by Chantria last updated on 11/Nov/16
prove      a^3 +b^3 +c^3 ≥3abc ; ∀a,b,c≥0
provea3+b3+c33abc;a,b,c0
Answered by aydnmustafa1976 last updated on 14/Nov/16
A.M≥G.M   ( a^3 +b^3 +c^3 )/3≥(a^3 .b^3 .c^3 )^(1/3)
A.MG.M(a3+b3+c3)/3(a3.b3.c3)1/3

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