Question Number 140503 by ERA last updated on 08/May/21
$$\boldsymbol{\mathrm{P}}\mathrm{rove}\:\mathrm{it} \\ $$$$\sqrt{\boldsymbol{{a}}+\sqrt{\boldsymbol{{b}}}}=\sqrt{\frac{\boldsymbol{{a}}+\sqrt{\boldsymbol{{a}}^{\mathrm{2}} +\boldsymbol{{b}}}}{\mathrm{2}}+}\sqrt{\frac{\boldsymbol{{a}}−\sqrt{\boldsymbol{{a}}^{\mathrm{2}} −\boldsymbol{{b}}}}{\mathrm{2}}} \\ $$
Commented by MJS_new last updated on 08/May/21
$$\mathrm{it}'\mathrm{s}\:\mathrm{wrong} \\ $$
Commented by MJS_new last updated on 10/May/21
$$\mathrm{it}'\mathrm{s}\:\mathrm{still}\:\mathrm{wrong} \\ $$
Commented by Dwaipayan Shikari last updated on 10/May/21
$${It}\:{should}\:{be}\:\sqrt{\frac{{a}+\sqrt{{a}^{\mathrm{2}} −{b}}}{\mathrm{2}}}+\sqrt{\frac{{a}−\sqrt{{a}^{\mathrm{2}} −{b}}}{\mathrm{2}}} \\ $$