prove-that-e-lnx-x-or-a-log-a-x-x-

Question Number 72344 by Rio Michael last updated on 27/Oct/19

p r o v e t h a t e^{l n x} = x

o r a^{{l o g}_{a} x} = x

Commented by Prithwish sen last updated on 27/Oct/19

let lnx = M

∴ e^{M} = x

putting the value of M

e^{lnx} = x proved

Commented by Tony Lin last updated on 27/Oct/19

l e t {l o g}_{a} x = y

a^{y} = x

\Rightarrow {l o g}_{a} x = y

\Rightarrow a^{{l o g}_{a} x} = x

Commented by Rio Michael last updated on 30/Oct/19

t h a n k y o u s i r s