prove-that-Log-z-1-z-2-Logz-1-Logz-2-with-condition-pi-lt-Argz-1-Argz-2-lt-pi-

Question Number 132626 by mohammad17 last updated on 15/Feb/21

$${prove}\:{that}\:{Log}\left({z}_{\mathrm{1}} {z}_{\mathrm{2}} \right)={Logz}_{\mathrm{1}} +{Logz}_{\mathrm{2}} \\ $$$${with}\:{condition}\:−\pi<{Argz}_{\mathrm{1}} +{Argz}_{\mathrm{2}} <\pi \\ $$

Commented by mohammad17 last updated on 16/Feb/21

$$????? \\ $$

Answered by guyyy last updated on 20/Feb/21

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