Question Number 66803 by Rio Michael last updated on 19/Aug/19

Commented by JDamian last updated on 19/Aug/19

Commented by Rio Michael last updated on 20/Aug/19

Commented by Cmr 237 last updated on 20/Aug/19

Answered by $@ty@m123 last updated on 20/Aug/19
![S=1+2+3+.....+n a=1, d=1 S=(n/2)[2a+(n−1)d] S=(n/2)[2+n−1] S=(1/2)n(n+1)](https://www.tinkutara.com/question/Q66838.png)