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Question Number 12092 by agni5 last updated on 13/Apr/17
Prove that tan 70°−tan 50°+tan 10° =(√3)
$$\mathrm{Prove}\:\mathrm{that}\:\:\mathrm{tan}\:\mathrm{70}°−\mathrm{tan}\:\mathrm{50}°+\mathrm{tan}\:\mathrm{10}°\:=\sqrt{\mathrm{3}} \\ $$

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