Menu Close

prove-that-the-equation-b-2-4ac-x-2-4-a-c-x-4-0-is-always-real-




Question Number 69778 by Rio Michael last updated on 27/Sep/19
prove that the equation     (b^2 −4ac)x^2  + 4(a + c)x −4 = 0 is always real.
provethattheequation(b24ac)x2+4(a+c)x4=0isalwaysreal.
Commented by prakash jain last updated on 28/Sep/19
Hi Rasheed  So glad to see that you are still here.
HiRasheedSogladtoseethatyouarestillhere.
Commented by prakash jain last updated on 27/Sep/19
Δ=(4(a+c))^2 −4×(−4)(b^2 −4ac)  =16a^2 +16c^2 +32ac+16b^2 −64ac  =16a^2 +16c^2 −32ac+16b^2   =16(a−c)^2 +16b^2   (a−c)^2  is always ≥0  b^2  is always ≥0  hence  Δ≥0  ⇒roots are always real  ■
Δ=(4(a+c))24×(4)(b24ac)=16a2+16c2+32ac+16b264ac=16a2+16c232ac+16b2=16(ac)2+16b2(ac)2isalways0b2isalways0henceΔ0rootsarealwaysreal◼
Commented by Abdo msup. last updated on 28/Sep/19
hello prakash you are absent for a long time...
helloprakashyouareabsentforalongtime
Commented by Rasheed.Sindhi last updated on 28/Sep/19
Welcome sir prakash.Happy to see  you in the forum! The forum needs you.
Welcomesirprakash.Happytoseeyouintheforum!Theforumneedsyou.
Commented by Rio Michael last updated on 28/Sep/19
thanks sir
thankssir
Answered by mind is power last updated on 27/Sep/19
a=b=c=0 false
a=b=c=0false
Commented by Rio Michael last updated on 27/Sep/19
what do you mean sir?
whatdoyoumeansir?
Commented by mind is power last updated on 27/Sep/19
your quation mean ax^2 +bx+c=0 ..Elet y root of E  ⇒(b^2 −4ac)y^2 +4(a+c)y−4=0?
yourquationmeanax2+bx+c=0..EletyrootofE(b24ac)y2+4(a+c)y4=0?
Commented by JDamian last updated on 28/Sep/19
In that case, there is no equation at all.
Inthatcase,thereisnoequationatall.
Answered by MJS last updated on 27/Sep/19
usually when dealing with  ax^2 +bx+c=0  it is clearly implied that a≠0  ⇒  x^2 +((4(a+c))/(b^2 −4ac))x−(4/(b^2 −4ac))=0; a, b, c ∈R∧b^2 −4ac≠0  x^2 +px+q=0 ⇔ x=−(p/2)±(√((p^2 /4)−q))  this is real for D=(p^2 /4)−q≥0  ⇒ D=4((a^2 −2ac+b^2 +c^2 )/((b^2 −4ac)^2 ))=4(((a−c)^2 +b^2 )/((b^2 −4ac)^2 ))>0 ⇒  ⇒ x∈R
usuallywhendealingwithax2+bx+c=0itisclearlyimpliedthata0x2+4(a+c)b24acx4b24ac=0;a,b,cRb24ac0x2+px+q=0x=p2±p24qthisisrealforD=p24q0D=4a22ac+b2+c2(b24ac)2=4(ac)2+b2(b24ac)2>0xR
Commented by Rio Michael last updated on 27/Sep/19
thank you sir
thankyousir

Leave a Reply

Your email address will not be published. Required fields are marked *