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Question-10023




Question Number 10023 by Tawakalitu ayo mi last updated on 21/Jan/17
Answered by ridwan balatif last updated on 21/Jan/17
6.2  Ni^(2+) +2e^− →Ni_((s)) →reduction           Zn^(2+) +2e^− →Zn_((s)) →oxidation        E^o cell=E_(reduction) ^o −E_(oxidation) ^o                      =−0.23−(−0.76)                     =−0.23+0.76                     =0.53 V
6.2Ni2++2eNi(s)reductionZn2++2eZn(s)oxidationEocell=EreductionoEoxidationo=0.23(0.76)=0.23+0.76=0.53V
Commented by Tawakalitu ayo mi last updated on 21/Jan/17
wow, God bless you sir.
wow,Godblessyousir.
Answered by ridwan balatif last updated on 21/Jan/17
6.1 reaction will be spontaneous if E^o >0, so          the answer is  (a).spontaneous  (b).spontaneous  (c).spontaneous  (f).spontaneous
6.1reactionwillbespontaneousifEo>0,sotheansweris(a).spontaneous(b).spontaneous(c).spontaneous(f).spontaneous
Commented by Tawakalitu ayo mi last updated on 21/Jan/17
i really appreciate sir.
ireallyappreciatesir.

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