Question Number 10190 by ketto last updated on 29/Jan/17
Commented by FilupSmith last updated on 29/Jan/17
$$\angle{ADB}=\mathrm{45}°\:\:\mathrm{and}\:\:\:\angle{BAD}=\mathrm{90}° \\ $$$$\therefore\angle{ABD}=\mathrm{45}° \\ $$$$\therefore\:{AB}={y}={AD} \\ $$$$\mathrm{let}\:{BD}={x} \\ $$$${x}^{\mathrm{2}} =\mathrm{2}{y}^{\mathrm{2}} \:\Rightarrow\:{y}=\frac{{x}}{\:\sqrt{\mathrm{2}}} \\ $$$$\left({x}=\sqrt{\mathrm{2}}{y}\right) \\ $$$$\: \\ $$$$\mathrm{thinking}.\:\mathrm{I}\:\mathrm{don}'\mathrm{t}\:\mathrm{remember}\:\mathrm{geometry}. \\ $$
Commented by sandy_suhendra last updated on 29/Jan/17
$$\mathrm{I}\:\mathrm{think}\:\mathrm{there}\:\mathrm{is}\:\mathrm{something}\:\mathrm{miss}\:\mathrm{in}\:\mathrm{this}\:\mathrm{question} \\ $$
Commented by FilupSmith last updated on 29/Jan/17
$$\mathrm{that}\:\mathrm{expains}\:\mathrm{it}.\:\mathrm{otherwise}\:\mathrm{this}\:\mathrm{would} \\ $$$$\mathrm{be}\:\mathrm{easy} \\ $$