Question Number 11020 by ridwan balatif last updated on 07/Mar/17
Answered by sandy_suhendra last updated on 08/Mar/17
Commented by sandy_suhendra last updated on 08/Mar/17
$$\left.\mathrm{1}\right)\:\mathrm{P}\left(−\frac{\mathrm{1}}{\mathrm{2}}\mathrm{A}\:,\:−\frac{\mathrm{1}}{\mathrm{2}}\mathrm{B}\right)\:=\:\mathrm{P}\left(\mathrm{5},\mathrm{7}\right) \\ $$$$\:\:\:\:\:\:\mathrm{PB}=\mathrm{r}=\sqrt{\frac{\mathrm{1}}{\mathrm{4}}\mathrm{A}^{\mathrm{2}} +\frac{\mathrm{1}}{\mathrm{4}}\mathrm{B}^{\mathrm{2}} −\mathrm{C}}\:=\:\sqrt{\mathrm{25}+\mathrm{49}+\mathrm{151}}\:=\:\mathrm{15}\:\:\:\: \\ $$$$\:\:\:\:\:\:\mathrm{AP}=\sqrt{\left(\mathrm{5}+\mathrm{7}\right)^{\mathrm{2}} +\left(\mathrm{7}−\mathrm{2}\right)^{\mathrm{2}} }\:=\:\mathrm{13} \\ $$$$\mathrm{jarak}\:\mathrm{terdekat}\:=\:\mathrm{AB}\:=\:\mathrm{15}−\mathrm{13}=\mathrm{2} \\ $$
Answered by sandy_suhendra last updated on 08/Mar/17
Commented by sandy_suhendra last updated on 08/Mar/17
$$\left.\mathrm{2}\right)\:\mathrm{P}\left(\mathrm{2},\mathrm{1}\right)\:\mathrm{dan}\:\mathrm{r}=\sqrt{\mathrm{32}}\:=\:\mathrm{4}\sqrt{\mathrm{2}} \\ $$$$\:\:\:\:\:\:\mathrm{AP}=\sqrt{\left(\mathrm{3}−\mathrm{2}\right)^{\mathrm{2}} +\left(\mathrm{2}−\mathrm{1}\right)^{\mathrm{2}} }\:=\:\sqrt{\mathrm{2}} \\ $$$$\:\:\:\:\mathrm{jarak}\:\mathrm{terjauh}\:=\:\mathrm{AB}\:=\mathrm{4}\sqrt{\mathrm{2}}\:+\:\sqrt{\mathrm{2}}\:=\:\mathrm{5}\sqrt{\mathrm{2}}\:\:\: \\ $$