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Question-11212




Question Number 11212 by uni last updated on 17/Mar/17
Answered by mrW1 last updated on 17/Mar/17
2x=25−5y=5(5−y)  x=((5(5−y))/2)  5−y must be even:  ⇒5−y=2k, k∈N  y=5−2k>0  x=5k>0  0<k<(5/2)  ⇒k=1 or 2  ⇒y=3 or 1  ⇒x=5 or 10    sum of y′s=3+1=4
2x=255y=5(5y)x=5(5y)25ymustbeeven:5y=2k,kNy=52k>0x=5k>00<k<52k=1or2y=3or1x=5or10sumofys=3+1=4

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